Question

factorise by Common Factor method p square square + PQ square + PQ R square

Answer 1

p^2 +pq^2 +pqr^2

=p×p+p×q×q+p×q×r×r

=p(p +q^2 +qr^2)

Answer 2

The factorisation of $P^{2} +PQ^{2} +PQR^{2}$ is $P[1+Q(Q +R^{2})]$.

Step-by-step explanation:

We have,

$P^{2} +PQ^{2} +PQR^{2}$

To factorise by common factor method = ?

∴ $P^{2} +PQ^{2} +PQR^{2}$

$=P\times P+PQ^{2} +PQR^{2}$

Taking P as common, we get

$=P(1+Q^{2} +QR^{2})$

$=P(1+Q\times Q +QR^{2})$

$=P[1+Q(Q +R^{2})]$

The factorisation of $P^{2} +PQ^{2} +PQR^{2}=P[1+Q(Q +R^{2})]$

Hence, the factorisation of $P^{2} +PQ^{2} +PQR^{2}$ is $P[1+Q(Q +R^{2})]$.