Math, asked by ayushcharkha, 10 months ago

factorise by completing square 4x^2 + 4√3x + 3​

Answers

Answered by Raj22222
3

Answer:

Roots are x = -\frac{\sqrt{3}}{2} Or x = -\frac{\sqrt{3}}{2}

Explanation:

Given Quadratic equation:

4x²+4√3x+3 = 0

=> 4x²+4√3x = -3

Divide each term by 4 , we get

x^{2}+\sqrt{3}x=\frac{-3}{4}

\implies x^{2}+2\times x\times \frac{\sqrt{3}}{2}=\frac{-3}{4}

\implies x^{2}+2\times x\times \frac{\sqrt{3}}{2}+\left(\frac{\sqrt{3}}{2}\right)^{2}=\frac{-3}{4}+\left(\frac{\sqrt{3}}{2}\right)^{2}

\implies\left(x+\frac{\sqrt{3}}{2}\right)^{2}\\=\frac{-3}{4}+\left(\frac{3}{4}\right)

\implies\left(x+\frac{\sqrt{3}}{2}\right)^{2}=0

\implies\left(x+\frac{\sqrt{3}}{2}\right)=0

Or

\implies\left(x+\frac{\sqrt{3}}{2}\right)=0

Therefore,

x = -\frac{\sqrt{3}}{2}

Or

x = -\frac{\sqrt{3}}{2}

[ Equal roots]

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Answered by ishaverma978
0

Answer:

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