Question

factorise by expressing into perfect square-9x^4-10x^2+2

Answer 1

hay!!

Dear friend -

$9 {x}^{4} - 10 {x}^{2} + 2 \\ {x}^{2} (9 {x}^{2} - 10 + 2) \\ {x}^{2}(9 {x}^{2} - 8) \\ ( {x}^{2} + 1)(9 {x}^{2} - 8) \\ \\ i \: hope \: its \: help \: you$

Answer 2

Hi friend, Harish here.

Here is your answer:

⇒ $9x^{4}-10x^{2}+1 = 9x^{4}-9x^{2} -x^{2}+1$

⇒ $9x^{2}(x^{2}-1)-1(x^{2}-1)$

⇒  $(9x^{2}-1)(x^{2}-1)$

⇒  $[(3x)^{2} - 1^{2}] (x^{2}-1)$

⇒  $\bold{(3x-1)(3x+1)(x-1)(x+1)}$
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Hope my answer is helpful to you.