factorise by identies. a^2y^3-2aby^2+b^2y
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Answer:-
( x² - y² )( a² - b² ) + 4abxy
= (ax)² - (ay)² - (bx)² + (by)² + 4abxy
= (ax)² + (by)² + 2axby - [ (ay)² + (bx)² - 2aybx ]
= [ ax + by ]² - [ ay - bx ]² < ----------- of form ( m² - n² )
= [ ax + by + ay - bx ] [ ax + by - ay + bx ]
= [ a(x+y) - b(x-y)] [ a(x-y) + b(x+y) ]
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Answer:
y(at-b) (at-b)
Step-by-step explanation:
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