Question

Factorise by middle term breaking:-
a) 45a²+62ab+21b²​

Answer 1

Answer:

2091 a2+ab+b2

Step-by-step explanation:

a) 45a²+62ab+21b²

• 2025a2 +62ab+4b2
• 2091a2+ab+b2

Answer 2

Answer:

Let p(x)=6x

2

+5x−6

Here we have to split middle term 5 into two parts such that their sum is 5 and product is 6×−6=−36

9 and −4 are such numbers whose sum is 5 and product is −36.

6x

2

+5x−6=6x

2

+9x−4x−6

=3x(2x+3)−2(2x+3)=(2x+3)(3x−2)