Question

factorise by middle term splitting
x²-10x+21

Answer 1

Answer:

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Answer 2

Answer:

(x-3)(x-7)

Step-by-step explanation:

First find the two NO. that are added to get (-10) and when they are multiplyed  they are 21 the numbers are (-7) and (-3)

$(-7)*(-3)=21\\(-7)+(-3)=10$

now split (-10) in the same way

$x^{2} -7x-3x+21=0$

now group the common

$x*(x-7)-3*(x-7)$

now join the two terms

$(x-7)*(x-3)$

There you have the answer.