Question

Factorise by midle term 3x^2+11x+6root of 3=0

Answer 1

Given equation

$3x^{2} +11x+6=0$

Solving, we get,

$3x^{2} +11x+6=0\\\implies 3x^{2} +2x+9x+6=0\\\implies x(3x+2)+3(3x+2)=0\\\implies (x+3)(3x+2)=0$

$x+3 = 0\\x = -3$

$3x+2 = 0\\\x = \dfrac{-2}{3}$

$\boxed{\boxed{\bold{Therefore, \ the \ factorised \ expression \ is \ (x+3)(3x+2) }}}}}$

                                                     

Answer 2

$3 {x}^{2} + 11x + 6 \\ \\ = > 3 {x}^{2} + 9x + 2x + 6 \\ \\ = > 3x(x + 3) + 2(x + 3) \\ \\ = > (3x + 2)(x + 3)$

Hence FACTORISED