Question

factorise by splitting middle term​

Answer 1

Answer:

$\huge\star\underbrace{\mathtt\red{⫷❥ᴀ᭄} \mathtt\green{n~ }\mathtt\blue{ §} \mathtt\purple{₩}\mathtt\orange{Σ} \mathtt\pink{R⫸}}\star\:$

Step-by-step explanation:

☆Let the polynomial be ax^2+bx+c

=>For middle term splitting.

☞Rule1=>You must have 2 factor of c whose product=c and sum =b

☞If a is not 1 ie it is a numeral quantity other than 1,then=>

• Reduce the whole equation by dividing if possible.
• Multiply a and c and apply rule1.

Example=>x^2+6x+8

=>x^2+6x+8

=>x^2+2x+4x+8 (Middle term splitting).

=>x(x+2)+4(x+2)

=>(x+4)(x+2)

☞So from here, x=-4 and x=-2(Application of rule1)

HOPE IT HELPS.

Answer 2

Step-by-step explanation:

Let the polynomial be ax^2+bx+c

=>For middle term splitting.

☞Rule1=>You must have 2 factor of c whose product=c and sum =b

☞If a is not 1 ie it is a numeral quantity other than 1,then=>

Reduce the whole equation by dividing if possible.

Multiply a and c and apply rule1.