Question

factorise by splitting middle term 2x² + 11x +12 ​

Answer 1

Answer:

$2 {x}^{2} - 11x + 12 = 0 \\ 2 {x}^{2} - (8 + 3)x + 12 = 0 \\ 2 {x}^{2} - 8x - 3x + 12 = 0 \\ 2x(x - 4) - 3(x - 4) = 0 \\ (x - 4)(2x - 3) = 0$

Answer 2

Answer:

$2x {}^{2} + 11x + 12 \\ = 2x {}^{2} + 8x + 3x + 12 \\ = 2x(x + 4) + 3(x + 4) \\ = (x + 4)(2x + 3)$