Factorise by splitting middle term
(Giving away points)
4x²-20x+25
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4x2-10x-10x+25
2x(2x-5)-5(2x-5)
(2x-5)(2x-5)
(2x-5)^2
2x(2x-5)-5(2x-5)
(2x-5)(2x-5)
(2x-5)^2
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Answer:
Step-by-step explanation:
4x^2-20x+25 split middle term such that by adding the splitted term you get what the middle term is and make sure that splitted terms must give you product of coefficient of x^2 and the constant . For example in this case 4*25=100.
4x^2-10x-10x+25 now by taking common term we get into what is stated below
2x(2x-5)-5x(2x-5)
(2x-5)(2x-5)
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