Question

factorise by splitting middle term x^2-17x+42​

Answer 1

Answer:

hey frnd here is your answer

Step-by-step explanation:

• x²-17x+42.

• x²-14x-3x+42

• (x-14)(x-3)

• so x=14 and x=3.

so your final answer is-

x=14 and x=7.

I hope you get the right answer

thanks for asking

plzz mark as brainlist....

Answer 2

$x^2-17x+42=0\\x^2-3x-14x+42=0$

Now let us see how we splitted it in -3 and -14.

Now we have to find such pairs either -ve or +ve which gives -17 on addition and +42 on multiplication.

So, only -3 + (-14) will give -17 on addition and +42 on multiplication.

Hence,

$x(x-3)-14(x-3)=0\\(x-3)(x-14)=0\\x=3\\or \\x=14$