Question

factorise by splitting middle term x∆2+3√3x-30​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

Answer:

x²+3√3x-30 = (x+5√3)(x-2√3)

Explanation:

Factorising x²+3√3x-30

Splitting the middle term, we get

= x²+5√3x-2√3x-30

= x²+5√3x-2√3x-2√3×5√3

= x(x+5√3)-2√3(x+5√3)

= (x+5√3)(x-2√3)

Therefore,

x²+3√3x-30 = (x+5√3)(x-2√3)

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