Question

Factorise by splitting the middle term 2x²+5x-12
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Answer 1

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$\longrightarrow \sf{2x}^{2} + 5x - 12 \: \: \: \: \: \: \: \: \: \: \: \\ \\ \longrightarrow \sf {2x}^{2} + 8x - 3x - 12 \: \: \\ \\ \longrightarrow \sf2x(x + 4) - 3(x + 4) \\ \\ \longrightarrow \sf (2x - 3)(x + 4) \: \: \: \: \: \: \: \: \:$

Answer 2

Answer:

2x*+5x-12=0

2x*+8x-3x-12=0

2x(x+4)-3(x+4)=0

(x+4)(2x-3)=0

either (x+4)=0 or (2x-3)=0

x+4=0,2x-3=0

x=-4,x=3/2