Factorise by splitting the middle term method
2 - a - a square
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given, 2-a-a² = 0
it can be written as a²+a-2=0
a²+2a-a-2=0
a(a+2)-1(a+2)=0
(a-1)(a+2)=0
a-1=0 or a+2=0
a=1 or a=-2
it can be written as a²+a-2=0
a²+2a-a-2=0
a(a+2)-1(a+2)=0
(a-1)(a+2)=0
a-1=0 or a+2=0
a=1 or a=-2
ananya1:
Thank you so much
The given question has no equation but expression. Why did you find the roots. Its only expression. which needs to be factorised.
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3
2 - a - a²
⇒2 - 2a + a - a²
⇒ 2(1 - a) + a(1 - a)
⇒ (1 - a)(2 + a)
⇒2 - 2a + a - a²
⇒ 2(1 - a) + a(1 - a)
⇒ (1 - a)(2 + a)
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