Question

factorise by splitting the middle term? please answering fast it's very important
(a) p2+6p+8

Answer 1

$= {p}^{2} + 6p + 8 \\ = {p}^{2} + (4 + 2)p + 8 \\ = {p}^{2} + 4p + 2p + 8 \\ = p(p + 4) + 2(p + 4) \\ = (p + 2)(p + 4) \\ = > p = - 2 ,- 4$

Answer 2

$\blue{ANSWER}$

${p}^{2} + 6p + 8 \\ \\ {p}^{2} + 2p + 4p + 8 = 0 \\ \\ p(p + 2) + 4(p + 2) = 0 \\ \\ p + 4 = 0 \: \: p + 2 = 0 \\ \\ p = - 4 \: and \: p = - 2$

$<b>$

hope it helps