factorise by substituting 5(x+y)²-6x-6y-8
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Let us solve the given expression 5(x+y) ^2 −6x−6y−8 as shown below:
5(x+y) ^2 −6x−6y−8
=5(x ^2 +y ^2 +2xy)−6x−6y−8 ( ∵ (a+b) ^2 =a ^2 +b ^2 +2ab)
=5x ^2 +5y ^2 +10xy−6x−6y−8
Hence, 5(x+y) ^2 −6x−6y−8 = 5x ^2 +5y ^2 +10xy−6x−6y−8.
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