Question

factorise by taking 3 as common Зх^2у – 3xy + 12х – 12​

Answer 1

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Answer 2

Step-by-step explanation:

$3 {x}^{2} y - 3xy + 12x - 12 \\ = 3xy(x - 1) + 12(x - 1) \\ = (3xy + 12)(x - 1) \\ = 3(xy + 4)(x - 1)$

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