Question

factorise by taking common factor +(3x + 4y) - x4

Answer 1

${(3x + 4y)}^{4} - {x}^{4}$
This could also be written as

${ ({(3x + 4y)}^{2} )}^{2} - {( {x}^{2}) }^{2}$

Now here we'll use and alzebric identity
${a}^{2} - {b}^{2} = (a+ b)(a- b)$


using this the given polynomial will become
$( {(3x + 4y)}^{2}+ {x}^{2} )(( {3x - 4y)}^{2}- {x}^{2})$



Again as you can see that the second part of this factoried polynomial is in the form of a^2 -b^2

using that identity again you'll get
$(( {3x + 4y)}^{2} + {x}^{2} )(3x - 4y + x)(3x + 4y - x)$