factorise by taking out common 4m(3n-5)+(3n-5)
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Answered by
1
Answer:
the factorisation of 4m(3n-5)+(3n-5) will be
(3n-5)(4m+1)
Answered by
4
Step-by-step explanation:
4m(3n-5)+(3n-5)
=(3n-5)[4m+1]
=(3n-5)(4m+1)
I think it is helpful for you
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