Question

factorise by taking out the common factor : ab(a^2+b^2-c^2)-bc(c^2-a^2-b^2)+ca(a^2+b^2-c^2)

Answer 1

ab(a²+b²-c²) -bc(c²-a²-b²) +ca(a²+b²-c²)

ab(a²+b²-c²) +bc(-c²+a²+b²) +ca(a²+b²-c²)

ab(a²+b²-c²) +bc(a²+b²-c²) +ca(a²+b²-c²)

(a²+b²-c²)(ab+bc+ca)

Or,

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{a+(b-c)(b+c)} [ab +bc+ca]

Answer 2

ab(a2+b2-c2)+bc(-c2+a2+b2)+ca(a2+b2-c2)

therefore,we take a2+b2-c2 common

(a2+b2-c2)(ab+bc+ca)