Question

factorise by using algebraic identities 49 a ^2 - 448b^2​

Answer 1

Answer:

(7a +21b) (7a - 2b) - 7b^2

49a^2 - 448b^2

splitting the second term

49a^2 - 441b^2 -7b^2

identity = a^2 - b^2 = (a+b) (a-b)

therefore, applying identity to the first two terms.

= (7a + 21b) (7a - 21b) - 7b^2