Question

factorise by using factor theoram 10y^2+3y-1​

Answer 1

Answer:

STEP

1

:

Equation at the end of step 1

((2•5y2) - 3y) - 1

STEP

2

:

Trying to factor by splitting the middle term

2.1 Factoring 10y2-3y-1

The first term is, 10y2 its coefficient is 10 .

The middle term is, -3y its coefficient is -3 .

The last term, "the constant", is -1

Step-1 : Multiply the coefficient of the first term by the constant 10 • -1 = -10

Step-2 : Find two factors of -10 whose sum equals the coefficient of the middle term, which is -3 .

-10 + 1 = -9

-5 + 2 = -3 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -5 and 2

10y2 - 5y + 2y - 1

Step-4 : Add up the first 2 terms, pulling out like factors :

5y • (2y-1)

Add up the last 2 terms, pulling out common factors :

1 • (2y-1)

Step-5 : Add up the four terms of step 4 :

(5y+1) • (2y-1)

Which is the desired factorization

Step-by-step explanation:

BTS ARMY

Answer 2

Answer: 10y^2+5y-2y-1

5y(2y+1) - 1(2y+1)

(5y-1) (2y+1)

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