Question

factorise by using factor theoram y^2-2y-8​

Answer 1

Answer:

Step-by-step explanation:

or,       y^2-2y-8

or,        y^2-4y+2y-8

or,         y(y-4)+2(y-4)

or,           (y+2) (y-4)

Answer 2

$\huge\bold\green{ solution }$

$y ^{2} - 2y - 8 \\ \\ y ^{2} + 2y - 4y - 8 \\ \\ y(y + 2) - 4(y + 2) \\ \\ (y + 2)(y - 4) \\ \\ y = - 2 \: and\: y = 4$