Question

factorise by using identity 27x^3-y^3

Answer 1

Answer :

Now,

27x^3 - y^3

= (3x)^3 - y^3

= (3x - y){(3x)^2 + (3x × y) + y^2}

= (3x - y)(9x^2 + 3xy + y^2),
which is the required factorization.

Identity rule :

a^3 - b^3

= (a - b)(a^2 + ab + b^2)

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Answer 2

Given: 27x^3-y^3
Applying the formula a^3-b^3= a^3-b^3-3ab(a+b), we get:
(27)^3-y^3-3(27)(y)(27-y)
19683-y^3-81y(27-y)
19683-y^3-2187y+81y^2




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