factorise by using identity a^3+343b^3
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Answered by
2
Answer :
Now,
a^3 + 343 b^3
= a^3 + (7b)^3
= (a + 7b) {a^2 - (a × 7b) + (7b)^2}
= (a + 7b) (a^2 - 7ab + 49 b^2),
which is the required factorization.
Identity Rule :
a^3 + b^3 = (a + b) (a^2 - ab + b^2)
#MarkAsBrainliest
Now,
a^3 + 343 b^3
= a^3 + (7b)^3
= (a + 7b) {a^2 - (a × 7b) + (7b)^2}
= (a + 7b) (a^2 - 7ab + 49 b^2),
which is the required factorization.
Identity Rule :
a^3 + b^3 = (a + b) (a^2 - ab + b^2)
#MarkAsBrainliest
Answered by
7
Heya!!
Here is yr answer...............
=> a³ + 343b³
=> a³ + (7b)³
It is in the form of -------------
a³ + b³ = (a+b) (a²-ab+b²)
a = a , b = 7b
= (a+7b) [ (a²-(a)(7b)+(7b)² ) ]
= (a+7b) (a²-7ab+49b²)
Hope it hlpz.....
Here is yr answer...............
=> a³ + 343b³
=> a³ + (7b)³
It is in the form of -------------
a³ + b³ = (a+b) (a²-ab+b²)
a = a , b = 7b
= (a+7b) [ (a²-(a)(7b)+(7b)² ) ]
= (a+7b) (a²-7ab+49b²)
Hope it hlpz.....
Anonymous:
bhai
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