Math, asked by harnakiya, 1 year ago

factorise by using identity a^3+343b^3

Answers

Answered by MarkAsBrainliest
2
Answer :

Now,

a^3 + 343 b^3

= a^3 + (7b)^3

= (a + 7b) {a^2 - (a × 7b) + (7b)^2}

= (a + 7b) (a^2 - 7ab + 49 b^2),
which is the required factorization.

Identity Rule :

a^3 + b^3 = (a + b) (a^2 - ab + b^2)

#MarkAsBrainliest
Answered by Anonymous
7
Heya!!

Here is yr answer...............

=> a³ + 343b³

=> a³ + (7b)³

It is in the form of -------------

a³ + b³ = (a+b) (a²-ab+b²)

a = a , b = 7b

= (a+7b) [ (a²-(a)(7b)+(7b)² ) ]

= (a+7b) (a²-7ab+49b²)

Hope it hlpz.....

Anonymous: bhai
Anonymous: yr identity is wrong
Anonymous: wait
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Anonymous: identity bhul gaya!!
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