factorise by using indrntity
1/36a^2b^2-16/49b^2c^2
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Answered by
21
1/36a^2b^2 - 16/49b^2c^2
= (1/6ab)^2 - (4/7bc)^2
= by using a^2 -b^2 formula we get
= (1/6ab+4/7bc)(1/6ab-4/7bc)
Hence factorised
Hope this helps you !!!!!!!
= (1/6ab)^2 - (4/7bc)^2
= by using a^2 -b^2 formula we get
= (1/6ab+4/7bc)(1/6ab-4/7bc)
Hence factorised
Hope this helps you !!!!!!!
Answered by
5
Answer:
Hey Mate!
Here is your answer...
i. 1/36a²b²-16/49b²c²
= (1/6ab)² - (4/7bc)²
= (1/6ab-4/7bc) (1/6ab+4/7bc)
Hope this will help you..
HAVE A GREAT DAY AHEAD !!
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