Question

factorise by using indrntity
1/36a^2b^2-16/49b^2c^2

Answer 1

1/36a^2b^2 - 16/49b^2c^2
= (1/6ab)^2 - (4/7bc)^2
= by using a^2 -b^2 formula we get
= (1/6ab+4/7bc)(1/6ab-4/7bc)

Hence factorised
Hope this helps you !!!!!!!

Answer 2

Answer:

Hey Mate!

Here is your answer...

i. 1/36a²b²-16/49b²c²

= (1/6ab)² - (4/7bc)²

= (1/6ab-4/7bc) (1/6ab+4/7bc)

Hope this will help you..

HAVE A GREAT DAY AHEAD !!