Math, asked by yangchendema, 1 month ago

factorise by using suitable identities
2 \sqrt{2} x {}^{3}  + 3 \sqrt{3} y {}^{3}

Answers

Answered by 2dots
1

Answer:

(√2x + √3y)(2x² - √6xy + 3y²)

Step-by-step explanation:

2√2x³ + 3√3y³

= (√2x)³ + (√3y)³

{ Using Identity a³ + b³ = (a + b)(a² - ab + b²) }

= (√2x + √3y)(2x² - √2x√3y + 3y²)

= (√2x + √3y)(2x² - √6xy + 3y²)

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