Math, asked by umarafroz84, 1 year ago

factorise by using suitable identity a⁴b⁴-c⁴​

Answers

Answered by RiyaParikh
5

Hey Mate, Here is your answer

 =  { (ab)}^{4}  -  {c}^{4}

 =  { {(ab)}^{2} }^{2}  -  { {c}^{2} }^{2}

 =  ( {a}^{2} {b}^{2}   +  {c}^{2} )( {(ab)}^{2}  -  {c}^{2} )

 =  ( {a}^{2} {b}^{2}   +  {c}^{2} )( ab + c)(ab - c)

Hope this helps, Please mark my answer as Brainliest.


umarafroz84: thank you
RiyaParikh: You're welcome
Answered by murarilalkedia00977
0

Answer:

= a⁴b⁴-c⁴

= (a²b²)²-(c²)²

= (ab+c)(ab-c)(a²b²+c²) ans.

Step-by-step explanation:

formula

a²-b²=(a+b)(a-b)

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