Question

factorise by using suitable indentity x2-y2+2x+1​

Answer 1

Answer:

Simple

Step-by-step explanation:

Given to find:x^2-y^2+2x+1

Regrouping the terms

By Regrouping given below$x ^{2} + 2x + 1 - y ^{2}$

Now, Indentity (a+b)^2=

$a^{2} + 2 \times a \times b + b ^{2}$

x^2+2(x) (1)+1^2-y^2(taking x as a and y as 1)

=(x+1)^2-y^2[now a^2-b^2=(a+b)(a-b)]

=[(x+1)+y][(x+1)-y]

=(x+y+1)(x-y+1)

Hope this helps....