Question

Factorise: c²-12c+20.​

Answer 1

Answer:

c = 2,10

Step-by-step explanation:

c^2 - (10+2)c + 20

c^2 - 10c - 2c + 20

c(c-10) - 2(c-10)

(c-2) (c-10)

c = 2,10

Answer 2

$STEP1:\\Trying \: to \: factor\\ \: by \: splitting \: the \: \\ middle \: term</p><p>\\</p><p> 1.1     Factoring  \:  c2-12c+20 \\</p><p></p><p>The \: first term \: is, \\  \: c2  its \: coefficient is   \: 1 .\\</p><p> \: The \: middle \: term \: \\ is,  \:  -12c   \: its \: coefficient \: is  -12 .\\</p><p>The \: last \: \\term, "the constant", is  +20 </p><p></p><p>Step-1 \: : Multiply \: the \: coefficient \: \\ of \: the \: first \: term \: by \: the \: \\constant  \:   1 • 20 = 20 </p><p></p><p>Step-2 : Find two factors of  20  whose sum \\equals the coefficient of the middle term, which is   -12 . \\ </p><p></p><p>     -20   +   -1   =   -21     -10 \\    +   -2   =   -12   That's it \\ </p><p></p><p></p><p>Step-3 : Rewrite the \\ polynomial splitting the \\ middle term using the two \\ factors found in \\ step 2 above,  -10  and  -2  \\ </p><p>                     c2 - 10c - 2c - 20</p><p> \\ </p><p>Step-4 : Add up the first 2 terms, pulling out like factors : \\ </p><p>                    c • (c-10)</p><p>              Add \:up\: the last 2 terms, pulling out common factors : \\ </p><p>                    2 • (c-10) \\ </p><p>Step-5 : Add up the four terms of step 4 : \\ </p><p>                    (c-2)  •  (c-10) \\ </p><p>             Which is the desired factorization</p><p> \\ </p><p>Final result : \\ </p><p></p><p>(c - 2) • (c - 10)</p><p></p><p>$

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