Math, asked by Tyneemax, 10 months ago

Factorise completely: 16m^3 - 54n^3

Answers

Answered by StudentDevansh
7

Answer:

2(2m-3n)(2m+6mn+3n)

Step-by-step explanation:

16m^3 - 54n^3

= 2(8m^3-27n^3)

= 2[(2m)^3 - 3n^3)]

= 2[(2m-3n)(2m+6mn+3n)]

                                             {using identity a^3-b^3 =(a-b)(a+ab+b)}

=2(2m-3n)(2m+6mn+3n)

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