Question

factorise completely

18. 4a2 - 12ab + 9b2 + 4a - 6b​

Answer 1

$4 {a}^{2} - 12ab + 9 {b}^{2} + 4a - 6b \\ {(2a)}^{2} - 2.2a.3b + {(3b)}^{2} + 2(2a - 3b) \\ {(2a - 3b)}^{2} + 2(2a - b) \\ (2a - 3b)(2a - 3b + 2)$