Question

factorise completely 36 - 36b + 9b²

Answer 1

Answer:

9(b-2)²

Step-by-step explanation:

9(b²-4b+4)

9[b²-(2)(b)(2)+(2)²] { (a-b)² = a²-2ab+b² }

9[ (b-2)² ]

or 9[ (b-2)(b-2) ]

Answer 2

$\large\mathtt { \underline{The \: value\: of \: b \: is \: 2}}$

Step-by-step explanation:

$\sf\longrightarrow{36 - 36b + {9b}^{2} = 0}$

$\sf{:⟹ {9b}^{2} - 36b + 36 = 0}$

$\sf{:⟹9( {b}^{2} - 4b + 4) = 0 }$

$\sf{:⟹ {b}^{2} - 4b + 4 = \frac{0}{9} }$

$\large\sf{ \underline{ \color{orange}{:⟹ {b}^{2} - 4b + 4 = 0}}}$

This equation is to be solved by the Sum and Product method.

$\sf{:⟹b(b - 2) - 2(b - 2)}$

$\sf{:⟹(b - 2)(b - 2)}$

$\large\sf{ \fbox{ \fcolorbox{red}{black}{∴ \: b = 2,2}}}$