Question

factorise completely
3ax-3ay-bx+by

Answer 1

Here ¡$ ¥oUr @n$

3ax-3ay-bx+by

3a(x-y)-b(x-y)

(x-y)(3a-b)...

xD.....¶ hOpE ¡T hElP$❤❤

Answer 2

FACTORISATION

Factorisation means turning sum of an algebric equation or expression into its product as a reverse of expanding values in brackets.

Given,

$\mathsf{3ax - 3ay - bx + by}$

This expression can be converted into two parts.

$\mathsf{ \bold{3ax - 3ay} - \bold{bx + by}}$

Now we can notice in first half of expression there is 3a common to both terms and in second half b is common to both terms. So by taking out common ,

$\mathsf{ \bold{3a(x - y)} - \bold{b(x + y)}}$

As we know when a term comes after negative sign the whole term becomes negative so,

$\mathsf{ \bold{3a(x - y)} - \bold{b(x - y)}}$

Now in the whole expression (x-y) is common so,

$\boxed{ \mathsf{ \bold{(x - y)(3a -b) }}}$