Question

Factorise completely 5b2+45b+90

Answer 1

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$5 {b}^{2} + 45b + 90 = 0 \\ \\ = > {b}^{2} + 9b + 18 = 0 \\ \\ = > {b}^{2} + (6 + 3)b + 18 = 0 \\ \\ = > {b}^{2} + 6b + 3b + 18 = 0 \\ \\ = > b(b + 6) + 3(b + 6) = 0 \\ \\ = > (b + 6)(b + 3) = 0 \\ \\ \\ b \: = - 6 \: and \: b \: = - 3$



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ஜ۩۞۩ஜ[ Hope it helps u ]ஜ۩۞۩ஜ

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Answer 2

$<b>hope it helps$ ✌️❣️