Question

factorise completely 6(a-b)^2+7(a-b)-3​

Answer 1

$\huge\boxed{\dag\sf\red{ANSWER}\dag}$

→ 6(a-b) ²+7(a-b) -3

→6(a²-2ab+b²) +7a-7b-3

→ 6a²-12ab+6b²+7a-7b-3