Factorise completely a^4-b^4
Plzzzzz answer it
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Answered by
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hiii,
a^4 - b^4
=(a^2)^2 - (b^2)^2
=(a^2+ b^2) (a^2 - b^2)
=(a^2 + b^2) (a + b) (a - b)
hope helps
a^4 - b^4
=(a^2)^2 - (b^2)^2
=(a^2+ b^2) (a^2 - b^2)
=(a^2 + b^2) (a + b) (a - b)
hope helps
jyotigupta0439oz78nt:
Thanks yaar
Answered by
1
Hello...
= a^4-b^4
= (a^2)^2 - (b^2)^2
As we know that a^2-b^2 = (a+b) (a-b)
= (a^2+b^2) (a^2-b^2)
= (a^2+b^2) (a+b) (a-b)
Hope It Helps You.
= a^4-b^4
= (a^2)^2 - (b^2)^2
As we know that a^2-b^2 = (a+b) (a-b)
= (a^2+b^2) (a^2-b^2)
= (a^2+b^2) (a+b) (a-b)
Hope It Helps You.
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