factorise completely using suitable identities :- 3z^5 - 27z^3
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Step-by-step explanation:
= 3z^5 - 27z^3
= 3z (z5 - 9z3)
= 3z3 (z^2 - 3^2)
= 3z3 (z - 3) (z + 3)
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