Question

factorise completely x^2/4y^2-1/7

Answer 1

Answer:

$\bf{\frac{x^2}{4y^2}-\frac{1}{7}=(\frac{x}{2y}-\frac{1}{\sqrt7})(\frac{x}{2y}+\frac{1}{\sqrt7})}$

Step-by-step explanation:

I have used the following algebraic identity to factorize the given polynomial

Formula used:

$a^2-b^2=(a-b)(a+b)$

Now,

$\frac{x^2}{4y^2}-\frac{1}{7}$

$=(\frac{x}{2y})^2-(\frac{1}{\sqrt7})^2$

$=(\frac{x}{2y}-\frac{1}{\sqrt7})(\frac{x}{2y}+\frac{1}{\sqrt7})$

$\implies\:\bf{\frac{x^2}{4y^2}-\frac{1}{7}=(\frac{x}{2y}-\frac{1}{\sqrt7})(\frac{x}{2y}+\frac{1}{\sqrt7})}$