Math, asked by sundechatanishka, 2 months ago

factorise completely x^4-81​

Answers

Answered by PrakritiAwasthi
0

= (x^2)^2 - (9)^2

= (x^2 - 9)(x^2 + 9).

Answered by sonaliakhilesh
1

x4-81

x4-81(x²)² - (9)²

x4-81(x²)² - (9)²(x² - 9)(x²+9)

x4-81(x²)² - (9)²(x² - 9)(x²+9)((x)²-(3)²)(x²+9)

x4-81(x²)² - (9)²(x² - 9)(x²+9)((x)²-(3)²)(x²+9)(x-3)(x+3)(x²+9)

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