Question

factorise completely x⁴-16​

Answer 1

Answer:

(x²+4)(x-2)(x+2)

I hope this answer may help you dear

Answer 2

Question :

Factorise $\mathtt{x^4-16}$

$\begin {gathered} \end {gathered}$

Answer :

$\mathtt{x^4 - 16 = (x^2 + 4)(x+2)(x-2)}$

$\begin {gathered} \end {gathered}$

Step - by - Step Explanation :

We have,

$\begin {aligned} (1) \ \bold {x^4 - 16} &\Rightarrow [(x^2)^2 - 4^2]\\\\&[\text{Using Identity a^2 - b^2 = (a + b)(a- b) }]\\\\&= \bf (x^2 + 4)(x^2 - 4)\end {aligned}$

$\begin {gathered} \end {gathered}$

This can further be Factorised by using the Same Identity given above . . .

$\begin {aligned} (2) \ \bold {(x^2 + 4)(x^2 - 4)} &\Rightarrow \Big [(x^2 + 4)[(x)^2 - 2^2]\Big ]\\\\&= \bf \Big [(x^2 + 4)(x + 2)(x - 2)\Big ] \end {aligned}$