Question

factorise d³-e³-1-3de​

Answer 1

We know that cube of 1 is 1 and number multiplied to 1 equal itself.

Hence , in given expression , 1 can be written as 1 ^ 3 anf - 3de can be written as - 3de × 1 .

Now , we know that x3 + y3 + z3 – 3xyz = (x + y + z) (x2 + y2 + z2 – xy – yz – zx).

Hence , d^3 - e ^ 3 - 1 ^3 - 3de

= ( d - e - 1 ) ( d^2 + e^2 + 1 + dy - y + d )

NOTE :

Here , x = d , y = - y and z = - 1

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