Question

factorise each of the following 121 p square minus one upon 9 p square​

Answer 1

Answer:

121 P^2 - (1/9) P^2

=P^2[11^2 -(1/3)^2]

=P^2[{11+(1/3)}{11-(1/3)}]

=P^2[(34/3)(32/3)

=({P^2)/9}1088