Question

factorise each of the following 27-125a-135a+225a2 ​

Answer 1

a) 125a3 + 27 + 135a + 225a2 = 125a3 + 225a2 + 135a + 27 = (5a)3 + 3 × (5a)2 × (3) + 3 × (5a) × (3)2 + 33 = (5a + 3)3 [Since, a3 + 3a2b + 3ab2 + b3 = (a + b)3] (b) 3m - 24m4 = 3m(1− 8m3) = 3m[13− (2m)3] = 3m [1 − 2m] [12 + 2m + (2m)2] [Since, (a3 − b3) = (a − b)(a2 + ab + b2 ] = 3m [1 − 2m] [1 + 2m + 4m2]

Answer 2

Answer:

(3-5a)^3

Step-by-step explanation:

As we know (a-b^3=a^3 -b^3-3a^2b

Hear, 27-125a^3-135a+225a^2

=(3)^3+(-5a)^3+3(3)^2(-5a)+3(3)-(-5a)^2

=(3-5a)^3

Thus, 27-125a^3-135a+225a^2

=(3-5a)^3

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