Factorise each of the following.
4x^2 - 16y^2 + 8y - 1
Answers
Answered by
11
4x^2 - 16y^2 + 8y - 1
= 4x^2 - 1 - 16y^2 + 8y
= (2x)^2 - (1)^2 - 8y (2y - 1)
= (2x - 1) (2x + 1) - 8y (2y - 1)
Answered by
24
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Answer:
4x²-(4y-1)(4y+1)
Step-by-step explanation:
=4x²-(16y²+4y+4y -1)
=4x²-(4y(4y-1)+1(4y-1))
=4x²-(4y-1)(4y+1).
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