Question

Factorise each of the following: 81 – p⁴ using identites ​

Answer 1

Answer: (9-$p^{2}$) (9+$p^{2}$)

Step-by-step explanation: Let us take (81-$p^{4}$) as ($9^{2}$-($p^{2}$)square)

Now You can use identity $a^{2}$-$b^{2}$ = (a-b) (a+b)

So it will be (9-$p^{2}$) (9+$p^{2}$)

This is Correct ans.

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Answer 2

Answer:

81 - p^4

(9)^2- (p^2)^2

Identity: a^2 - b^2 = ( a+b)( a-b)

a=9 , b=p^2

(9+p^2) ( 9-p^2)

(9+p^2) { (3)^2 - (p)^2 }

(9+p^2)(3+p)(3-p) Ans..

Step-by-step explanation:

Hope it helps mate!