Question

Factorise each of the following expression completely
-a²+2a+35

(middle term breaking)​

Answer 1

Answer:

हिंदी में खोजें

a² 2 ए 35

Search Results

How to solve your problem

−2+2+35

-a^{2}+2a+35−a2+2a+35

Grouping

1

Common factor

−2+2+35

-a^{2}+2a+35−a2+2a+35

−1(2−2−35)

-1(a^{2}-2a-35)−1(a2−2a−35)

2

Use the sum-product pattern

−1(2−2−35)

-1(a^{2}{\color{#c92786}{-2a}}-35)−1(a2−2a−35)

−1(2+5−7−35)

-1(a^{2}+{\color{#c92786}{5a}}{\color{#c92786}{-7a}}-35)−1(a2+5a−7a−35)

3

Common factor from the two pairs

−1(2+5−7−35)

-1(a^{2}+5a-7a-35)−1(a2+5a−7a−35)

−1((+5)−7(+5))

-1(a(a+5)-7(a+5))−1(a(a+5)−7(a+5))

4

Rewrite in factored form

−1((+5)−7(+5))

-1(a(a+5)-7(a+5))−1(a(a+5)−7(a+5))

−1(−7)(+5)

-1(a-7)(a+5)−1(a−7)(a+5)

Solution

−1(−7)(+5)

Answer 2

Step-by-step explanation:

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