Question

Factorise each of the following expressions
completely
$169n {}^{2} - 52n + 4$

​

Answer 1

Required Answer:-

Given To Factorise:

• 169n² - 52n + 4

Solution:

We have,

= 169n² - 52n + 4

This can be written as,

= (13n)² - 2 × (13n) × 2 + (2)²

We know that,

➡ (a - b)² = a² - 2ab + b²

Therefore,

= (13n)² - 2 × (13n) × 2 + (2)²

= (13n - 2)²

This can't be factorised more.

★ Hence, the factorised form of the polynomial is (13n - 2)²

Answer:

• Factorised form is (13n - 2)²

More Identities:

• (a + b)² = a² + 2ab + b²
• a² - b² = (a + b)(a - b)
• (a + b)³ = a³ + 3ab(a + b) + b³
• (a - b)³ = a³ - 3ab(a - b) - b³

Answer 2

Step-by-step explanation:

i hope it may help you ..