Factorise each of the following:
(i) 27y3 + 12523
(ii) 64m3 - 343n3
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Answer:
(i) 27y³ + 125z³
Using identity,
x³ + y³ = (x + y) (x² – xy + y²)
27y³ + 125z³
= (3y)³ + (5z)³
= (3y + 5z) {(3y)² – (3y)(5z) + (5z)²}
= (3y + 5z) (9y² – 15yz + 25z²)
(ii) 64m³ – 343n³
Using identity,
x³ – y³= (x – y) (x² + xy + y² )
64m³– 343n³
=(4m)³ – (7n)³
=(4m - 7n) {(4m)² + (4m)(7n) + (7n)²}
= (4m-7n) (16m²+ 28mn + 49n²)
Hope this will help you.....
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