factorise each of the following p^3+27
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38
Answer:
p^3+27
= p^3 + 3^3 [a^3 + b^3 =(a+b) (a^2 - ab + b^2) ]
= (p + 3) (p^2 - 3p - 9)
Therefore, p^3 + 27 = (p+3) (p^2 - 3p - 9)
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